2w^2+8w+22=(w-1)

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Solution for 2w^2+8w+22=(w-1) equation: 



2w^2+8w+22=(w-1)

We move all terms to the left:

2w^2+8w+22-((w-1))=0



We calculate terms in parentheses: -((w-1)), so:

(w-1)

We get rid of parentheses

w-1

Back to the equation:

-(w-1)



We get rid of parentheses

2w^2+8w-w+1+22=0

We add all the numbers together, and all the variables

2w^2+7w+23=0

a = 2; b = 7; c = +23;
Δ = b2-4ac
Δ = 72-4·2·23
Δ = -135
Delta is less than zero, so there is no solution for the equation

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